SOLUTION: Can someone help me here? I need to solve the system by addition or substitution 3x - 4y = 8 6x - 2y = 10 Thanks, Jamie

Algebra ->  Systems-of-equations -> SOLUTION: Can someone help me here? I need to solve the system by addition or substitution 3x - 4y = 8 6x - 2y = 10 Thanks, Jamie      Log On


   

Question 59521: Can someone help me here?
I need to solve the system by addition or substitution
3x - 4y = 8
6x - 2y = 10
Thanks,
Jamie
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
1st: 3x - 4y = 8
2nd: 6x - 2y = 10
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Multiply 1st by 2 to get:
3rd: 6x-8y=16
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Subtract 2nd from 3rd to get:
-6y=6
y=-1
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Substitute into 1st so solve for "x":
3x-4(-1)=8
3x=4
x=4/3
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Solution:
x=4/3; y=-1
Cheers,
Stan H.