SOLUTION: The perimeter of a rectangle is 160 ft. One fourth the length is the same as twice the width. Find the dimensions of the rectangle.

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Question 4880: The perimeter of a rectangle is 160 ft. One fourth the length is the same as twice the width. Find the dimensions of the rectangle.
Answer by longjonsilver(2297) About Me  (Show Source):
You can put this solution on YOUR website!
Let length = x
Length width = y

we know that x+x+y+y=160 --> 2x+2y=160

Also, x/4 = 2y --> x = 8y.

Put this second equation into the first, to give 2(8y) + 2y = 160
16y+2y = 160
18y = 160
y = 80/9
y = 8.89 ft (to 2dp)

--> as x = 8y, we get x = 71.11 (to 2dp)

Check: add 2 lots of each length --> do you get 160?

jon