SOLUTION: The sum of two numbers is 41 and the difference is 5. What are the numbers? i would like the answer but i would like to know how to do this

Algebra ->  Systems-of-equations -> SOLUTION: The sum of two numbers is 41 and the difference is 5. What are the numbers? i would like the answer but i would like to know how to do this      Log On


   



Question 447783: The sum of two numbers is 41 and the difference is 5. What are the numbers?
i would like the answer but i would like to know how to do this

Found 3 solutions by mananth, ikleyn, josgarithmetic:
Answer by mananth(16949) About Me  (Show Source):
You can put this solution on YOUR website!
let one number be x
other be y .... x>y
x+y = 41
x-y =5
Add the two equations
2x=46
/2
x=23
ao y= 41-23=18
(23, 18)

Answer by ikleyn(53616) About Me  (Show Source):
You can put this solution on YOUR website!
.
The sum of two numbers is 41 and the difference is 5. What are the numbers?
i would like the answer but i would like to know how to do this
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        Problems of this kind can be also easy solved mentally.
        Below I show such a solution.


So, you have two numbers, whose sum is 41 and the difference is 5.


Mentally, diminish the greater number by 5.


Then you will have two equal numbers, their difference will be 0, 
and their sum will be 5 units less than 41, i.e. 41-5 = 36.


But if two equal numbers sum to 36, then the numbers are 18 units.


Thus, your lesser number is 18, while the greater number is 18+5 = 23.


ANSWER.  The numbers are 18 and 23, obtained MENTALLY.

Wow !



Answer by josgarithmetic(39733) About Me  (Show Source):
You can put this solution on YOUR website!
numbers m and n
sum is 41
difference is 5

system%28m%2Bn=41%2Cm-n=5%29

If adding the equation,
2m=46
m=23

using m
23-n=5
n=23-5
n=18

The numbers are 23 and 18.