SOLUTION: need help with this problem. x-y= 3(1) 3x-3z= 15(2) 3y+z= 6(3)

Algebra ->  Systems-of-equations -> SOLUTION: need help with this problem. x-y= 3(1) 3x-3z= 15(2) 3y+z= 6(3)      Log On


   

Question 425647: need help with this problem.
x-y= 3(1)
3x-3z= 15(2)
3y+z= 6(3)
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
x-y= 3
3x-3z= 15
3y+z= 6
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Solve for "x" in 2nd equation:
x = z+5
Solve for "y" in 3rd equation:
y = (-z/3) + 2
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Substitute into the 1st equation and solve for "z"
(z+5)-[(-z/3)+2] = 3
(4/3)z +5 - 2 = 3
(4/3)z = 0
z = 0
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Solve for x and for "y":
x = z+5
x = 5
----
y = (-z/3)+2
y = 2
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Cheers,
Stan H.
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