SOLUTION: Given y is two times x, z is three times x, and x + y + 3z = 12. What are the values of x, y and z? (1, 2 and 3?)

Algebra ->  Systems-of-equations -> SOLUTION: Given y is two times x, z is three times x, and x + y + 3z = 12. What are the values of x, y and z? (1, 2 and 3?)      Log On


   

Question 381720: Given y is two times x, z is three times x, and x + y + 3z = 12. What are the values of x, y and z? (1, 2 and 3?)
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi,         

x + y + 3z = 12  y = 2x and z = 3x

x + 2x + 3(3x) = 12

 12x = 12

   x = 1

You are absolutely correct:  x = 1, y = 2  and z = 3

CHECKING the Answer

 1 + 2 + 3*3 = 12