SOLUTION: <img src="http://img221.imageshack.us/img221/5731/eq10.jpg">

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Question 378107:
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
1) Add corresponding sides of the equations: 2x%5E2+=+10, or x%5E2+=+5. Substituting this into the top equation, we get y%5E2+=+4. Thus there are 4 solutions: (-sqrt%285%29, -2), (-sqrt%285%29, 2), (sqrt%285%29, -2), (sqrt%285%29, 2). (They represent the intersection points of a circle centered at (0,0) with radius 3 and a hyperbola with transverse axis corresponding to the x-axis.)

2)Multiply the top eq'n by 2, and then add corresponding sides: 8x%5E2+=+72, or x%5E2+=+9. Substituting into the lower eq'n, we get 16y%5E3+=+-2, or y%5E3+=+-1%2F8, or y = -1/2. Thus there are 2 solutions: (-3, -1/2) and (3, -1/2).

3) Multiply the top eq'n by 2, and then add corresponding sides: 1/y = 3, or y = 1/3. Substituting into the top eq'n, we get: 2%2Fx+-9+=+1, or 2%2Fx+=+10, or x = 1/5.