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Algebra: Systems of equations that are not linear
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Question 378099
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Answer by
user_dude2008(1862)
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x-2y=2
x=2y+2
y^2-x^2=2x+4
y^2-(2y+2)^2=2(2y+2)+4
y^2-(4y^2+8y+4)=4y+4+4
y^2-4y^2-8y-4=4y+8
y^2-4y^2-8y-4-4y-8=0
-3y^2-12y-12=0
y^2+4y+4=0
(y+2)^2=0
y+2=0
y=-2
x=2y+2=2(-2)+2=-4+2=-2
Answers: x=-2, y=-2