SOLUTION: What are the integral roots of x^2-7x-8=o?

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Question 303181: What are the integral roots of x^2-7x-8=o?
Found 2 solutions by Earlsdon, nyc_function:
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Find the roots of:
x%5E2-7x-8+=+0 Factor.
%28x%2B1%29%28x-8%29+=+0 Apply the zero product rule.
x%2B1+=+0 or x-8+=+0 so...
highlight%28x+=+-1%29 or highlight%28x+=+8%29
graph%28400%2C400%2C-10%2C10%2C-25%2C5%2Cx%5E2-7x-8%29

Answer by nyc_function(2741) About Me  (Show Source):
You can put this solution on YOUR website!
What two numbers when multiplied together will yield -8 but when added will yield -7?
How about -8 and 1?
Then x^2 - 7x - 8 = 0 factors out to be (x + 1)(x - 8).
Now set each factor to equal zero and solve for x.
x + 1 = 0
x = -1.
x - 8 = 0
x = 8
The roots are x = -1 and x = 8.
Originally, I thought this was a calculus question after reading the word INTEGRAL in the sentence.