SOLUTION: how do you figure this problem out m^2+3m+2=0

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Question 27366: how do you figure this problem out m^2+3m+2=0
Answer by Alwayscheerful(414) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation am%5E2%2Bbm%2Bc=0 (in our case 1m%5E2%2B3m%2B2+=+0) has the following solutons:

m%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%283%29%5E2-4%2A1%2A2=1.

Discriminant d=1 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28-3%2B-sqrt%28+1+%29%29%2F2%5Ca.

m%5B1%5D+=+%28-%283%29%2Bsqrt%28+1+%29%29%2F2%5C1+=+-1
m%5B2%5D+=+%28-%283%29-sqrt%28+1+%29%29%2F2%5C1+=+-2

Quadratic expression 1m%5E2%2B3m%2B2 can be factored:
1m%5E2%2B3m%2B2+=+1%28m--1%29%2A%28m--2%29
Again, the answer is: -1, -2. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B3%2Ax%2B2+%29

Hope this helps!