SOLUTION: solve each system of equatioins by using substitution
m+n=20
m-n=-4
work: m+n=20
-n -n
----------
20-n
m-n=-4
20-n-n=-4
(20-n)=-4
-4
Algebra ->
Systems-of-equations
-> SOLUTION: solve each system of equatioins by using substitution
m+n=20
m-n=-4
work: m+n=20
-n -n
----------
20-n
m-n=-4
20-n-n=-4
(20-n)=-4
-4
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Question 239833: solve each system of equatioins by using substitution
m+n=20
m-n=-4
work: m+n=20
-n -n
----------
20-n
m-n=-4
20-n-n=-4
(20-n)=-4
-4n-80
~ thats all i could come up with.... Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! m+n=20
m=20-n
Now replace m in the following equation with 20-n
m-n=-4
(20-n)-n=-4
-2n=-4-20
-2n=-24
n=-24/-2
n=12 ans.
m+12=20
m=20-12
m=8 ans.
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