SOLUTION: hey can someone plz help me solve this system of equations {{{2x^2-6x+4=0}}} 3y-12=-4x thank you

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Question 233290: hey can someone plz help me
solve this system of equations
2x%5E2-6x%2B4=0
3y-12=-4x
thank you
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
2x%5E2-6x%2B4=0
x%5E2-3x%2B2=0
(x-2)*(x-3) = 0
x = 2 or x = 3
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3y-12=-4x
y = (12-4x)/3
x = 2, y = 4/3
x = 3, y = 0