SOLUTION: Please help me with the following word problem, I can not do percentages at all and I can not figure out the answer. Thank you so much! A chemist wants to mix a 5% alcohol solutio

Algebra ->  Systems-of-equations -> SOLUTION: Please help me with the following word problem, I can not do percentages at all and I can not figure out the answer. Thank you so much! A chemist wants to mix a 5% alcohol solutio      Log On


   



Question 209326: Please help me with the following word problem, I can not do percentages at all and I can not figure out the answer. Thank you so much! A chemist wants to mix a 5% alcohol solution with a 25% alcohol solution to obtain 8 liters of a 20% alcohol solution. How much (in liters) of the 25% solution should she use?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
What might help you is to always
remember that percent means
"per one-hundred", so whenever
you see %, you must divide by
100.
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A good question to ask with this
problem is: "How much water and
how much alcohol end up in the
final solution?
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Let a= liters of the 5% solution added
Let b= liters of the 25% solution added
------------------------------
The equation to solve in words is:
(alcohol in 5% solution)+(alcohol in 25% soltion)/(alcohol + water in 20% solution) = 20%
So, I can write:
(1) %28.05a+%2B+.25b%29+%2F+8+=+.2
(2) a+%2B+b+=+8
Multiply both sides of (1) by 8
(1) .05a+%2B+.25b++=+8%2A.2
(1) .05a+%2B+.25b+=+1.6
Multiply both sides of (2) by .05 and subtract from (1)
(2) .05a+%2B+.05b+=+.05%2A8
(2) .05a+%2B+.05b+=+.4
And, subtracting:
(1) .05a+%2B+.25b+=+1.6
(2) -.05a+-+.05b+=+-.4
.2b+=+1.2
b+=+6
She should use 6 liters of the 25% solution
check answer:
(2) a+%2B+b+=+8
a+%2B+6+=+8
a+=+2
Go back to (1)
(1) %28.05a+%2B+.25b%29+%2F+8+=+.2
%28.05%2A2+%2B+.25%2A6%29+%2F+8+=+.2
.05%2A2+%2B+.25%2A6+=+1.6
.1+%2B+1.5+=+1.6
1.6+=+1.6
It always helps if you can sum up the problem in
an equation with words like I did (It helps me a lot)