SOLUTION: The perimeter of a triangle is 105 inches. The longest side is 22 inches longer than the shortest side. The sum of the lengths of the two shorter sides is 15 inches more than the l
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Question 196293This question is from textbook College Algebra
: The perimeter of a triangle is 105 inches. The longest side is 22 inches longer than the shortest side. The sum of the lengths of the two shorter sides is 15 inches more than the length of the longest side. Find the lengths of the sides of the triangle. This question is from textbook College Algebra
You can put this solution on YOUR website! Let L=longest side, s=shortest, b=in between side.
a) L+b+s=105
b) L=s+22
c) b+s=L+15
c) b+s=s+22+15 substitute s+22 for L
c) b=37 subtract s from each side.
a) s+22+37+s=105
a) 2s=105-59
a) 2s=46
a) s=23
b) L=23+22
b) L=45
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Ed
