SOLUTION: Find an equation of the lne containing the given pair of points. (1/6, -1/3) and (5/6, 5) What is the equation of the line? y= ______

Algebra ->  Systems-of-equations -> SOLUTION: Find an equation of the lne containing the given pair of points. (1/6, -1/3) and (5/6, 5) What is the equation of the line? y= ______      Log On


   



Question 160010: Find an equation of the lne containing the given pair of points.
(1/6, -1/3) and (5/6, 5)
What is the equation of the line?
y= ______

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
Y=mX+b
(1/6, -1/3) and (5/6, 5)
SLOPE (m)=(5+1/3)/(5/6-1/6)
m=[(15+1)/3]/(4/6)
m=(16/3)*3/2
m=16/2
8 IS THE SLOPE.
5=8*5/6+b
5=40/6+b
b=5-40/6
b=5-20/3
b=(5*3-20)/3
b=(15-20)/3
b=-5/3 THE Y INTERCEPT.
THUS THE LINE EQUATION IS:
Y=8X-5/3
+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+8x+-5%2F3%29+ (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, 8x -5/3).