SOLUTION: please help me solve {{{1+2/(b-1)=2/(b^2-b)}}}. THANK YOU

Algebra ->  Systems-of-equations -> SOLUTION: please help me solve {{{1+2/(b-1)=2/(b^2-b)}}}. THANK YOU      Log On


   

Question 155556: please help me solve 1%2B2%2F%28b-1%29=2%2F%28b%5E2-b%29. THANK YOU
Answer by sim9739(6) About Me  (Show Source):
You can put this solution on YOUR website!
1%2B2%2F%28b-1%29=2%2F%28b%5E2-b%29
%28%28b-1%29%2B2%29%2F%28b-1%29=2%2F%28b%5E2-b%29
%28b%2B1%29%2F%28b-1%29=2%2Fb%2A%28b-1%29
b%2B1+=+2%2Fb
b%5E2%2Bb+-2=0
%28b%2B2%29%28b-1%29+=+0
so b = 1 or b = -2,
But if b= 1, then the term 2%2F%28b-1%29 = 2/0 and it is not defined
Hence, b=-2