SOLUTION: Hello. I have a very important test on Friday and I'm having some trouble with these types of problems. I would very much appreciate if you could explain to me the steps as to ho

Algebra ->  Systems-of-equations -> SOLUTION: Hello. I have a very important test on Friday and I'm having some trouble with these types of problems. I would very much appreciate if you could explain to me the steps as to ho      Log On


   

Question 13938: Hello. I have a very important test on Friday and I'm having some trouble with these types of problems. I would very much appreciate if you could explain to me the steps as to how to solve this problem and some tips as to how to solve this problems in general because they are all different.
%28x-1%29%5E2%2By%5E2=1
x%5E2%2B%28y-1%29%5E2=1
I figured out that x^2=y^2 and determined that the two points of intersection are (0,0) and (1,1) but I get a third point and I don't know why. I appreciate your help.
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
What you have here are the equations of two circles. The standard form is: %28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2
The first has its center at (1, 0) and its radius is 1.
The second has its center at (0, 1) and its radius is also 1.
These two circles intersect at only two points which you have correctly identified.
How are you getting a third point of intersection?
Graph the two equations and you will see the two points of intersection.