Question 137051: solve:
2y^2+xy=5
4y+x=7
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! solve:
2y^2+xy=5
4y+x=7
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Solve the 2nd equation for "x":
x = 7-4y
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Substitute that into the 1st equation and solve for "y":
2y^2+(7-4y)y = 5
2y^2+7y-4y^2 = 5
2y^2-7y+5 = 0
y = [7 +- sqrt(49-4*2*5)]/4
y = [7 +- 3]/4
y = 5/2 or y = 1
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No solve for "x":
If y = 5/2, x = 7-4*(5/2) = -3
If y = 1, x = 7-4*1 = 3
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Solutions: (-3,5/2) or (3,1)
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Cheers,
Stan H.
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