SOLUTION: The perimeter of a rectangle is 160 feet. One-fourth the length is the same as the width. Find the dimensions of this rectangle. I've tried setting up 2 equations but I'm not sur

Algebra ->  Systems-of-equations -> SOLUTION: The perimeter of a rectangle is 160 feet. One-fourth the length is the same as the width. Find the dimensions of this rectangle. I've tried setting up 2 equations but I'm not sur      Log On


   

Question 1189076: The perimeter of a rectangle is 160 feet. One-fourth the length is the same as the width. Find the dimensions of this rectangle.
I've tried setting up 2 equations but I'm not sure how.
Thank you
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
L and w
Length and Width;

L%2Bw=160%2F2=80
system%28w=L%2F4%2COR%2CL=4w%29

If you are trying to setup using two equations, this can be system%28L%2Bw=80%2Cand%2CL=4w%29.

Create and solve THIS:
4w%2Bw=80
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