SOLUTION: f(x) = 3x + 2 Could you please explain to me how to graph this.

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Question 117613: f(x) = 3x + 2
Could you please explain to me how to graph this.

Found 4 solutions by jim_thompson5910, checkley71, Fombitz, josmiceli:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: Graphing Linear Equations
In order to graph y=3%2Ax%2B2 we only need to plug in two points to draw the line

So lets plug in some points

Plug in x=-3

y=3%2A%28-3%29%2B2

y=-9%2B2 Multiply

y=-7 Add

So here's one point (-3,-7)




Now lets find another point

Plug in x=-2

y=3%2A%28-2%29%2B2

y=-6%2B2 Multiply

y=-4 Add

So here's another point (-2,-4). Add this to our graph





Now draw a line through these points

So this is the graph of y=3%2Ax%2B2 through the points (-3,-7) and (-2,-4)


So from the graph we can see that the slope is 3%2F1 (which tells us that in order to go from point to point we have to start at one point and go up 3 units and to the right 1 units to get to the next point) the y-intercept is (0,2)and the x-intercept is (-0.666666666666667,0) ,or (-2%2F3,0)


We could graph this equation another way. Since b=2 this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0,2).


So we have one point (0,2)





Now since the slope is 3%2F1, this means that in order to go from point to point we can use the slope to do so. So starting at (0,2), we can go up 3 units



and to the right 1 units to get to our next point


Now draw a line through those points to graph y=3%2Ax%2B2


So this is the graph of y=3%2Ax%2B2 through the points (0,2) and (1,5)

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
y=3x+2
the y intercept=2 or (0,2)
now set y=0 & solve for x:
0=3x+2
3x=-2
x=-2/3 answer or (-2/3,0)
plot these 2 points & draw a line through them:
andyou have the following graph.
+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+y=+3x+%2B2%29+ (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = 3x +2).

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Make a table of value of the form (x,f(x)).
Pick values.
For x=0, f(x)=3(0)+2=2
For x=1, f(x)=3(1)+2=5
For x=2, f(x)=3(2)+2=8
Don't forget some negative values also.
For x=-1, f(x)=3(-1)+2 = -1
For x=-2, f(x)=3(-2)+2 = -4
Then get graph paper.
Draw an x-axis horizontally.
Draw an f(x) or y-axis vertically.
Then plot the points.
(0,2) Zero units on the x, 2 units up (positive) on the y.
drawing%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2Cgrid%28+1+%29%2Ccircle%280%2C2%2C.3%29%29
(1,5) 1 unit to the right(positive) on the x, 5 units up on the y.

(2,8)Two units on the x, 8 units up on the y.

(-1,-1) One unit left (negative), one unit down (negative) on the y.

(-2,-4)

Then finally you connect all the points together.
This function actually represents a straight line.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
First pick a few values for x, then see what
f%28x%29 is for that value. Make a little chart of these
x and f%28x%29 combinations. Some good x
values to use are 0, 1 -1
f%28x%29+=+3x+%2B+2
-------------------
f%280%29+=+3%2A0+%2B+2
f%280%29+=+2
-------------------
f%28-1%29+=+3%2A%28-1%29+%2B+2
f%28-1%29+=+-3+%2B+2
f%28-1%29+=+-1
-------------------
f%281%29+=+3%2A1+%2B+2
f%281%29+=+5
-------------------
f%280%29+=+2
f%28-1%29+=+-1
f%281%29+=+5
These are the three points you can plot
------------------
You can also write them as
(x,y)
The three points are
(0,2)
(-1,-1)
(1,5)
There are lots of other oints you can plot, but these
are a good start. The graph looks like
+graph%28+600%2C+600%2C+-6%2C+6%2C+-8%2C+8%2C+3x+%2B+2%29+