SOLUTION: A chemical company makes two brands of antifreeze. The first brand is 65% pure antifreeze, and the second brand is 90% pure antifreeze. In order to obtain 110 gallons of a mixture
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-> SOLUTION: A chemical company makes two brands of antifreeze. The first brand is 65% pure antifreeze, and the second brand is 90% pure antifreeze. In order to obtain 110 gallons of a mixture
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Question 1145220: A chemical company makes two brands of antifreeze. The first brand is 65% pure antifreeze, and the second brand is 90% pure antifreeze. In order to obtain 110 gallons of a mixture that contains 70% pure antifreeze, how many gallons of each brand of antifreeze must be used? Answer by ikleyn(52780) (Show Source):
x = gallons of the 90% mixture.
The equation
0.65*(110-x) + 0.90x = 0.7*110
The solution is x = = 22 gallons.
ANSWER. 22 gallons of the 90% mixture and 110-22 = 88 gallons of the 65% mixture.
CHECK. 0.65*88 + 0.9*22 = 77 gallons of the pure antifreeze in ingredients, and
0.7*110 = 77 gallons of the pure antifreeze in the final mixture. ! Correct !
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