SOLUTION: The difference between the length and width of a rectangle is 2 units. The perimeter is 40 units. Write and solves system of equations to determine the length and width of the rect

Algebra ->  Systems-of-equations -> SOLUTION: The difference between the length and width of a rectangle is 2 units. The perimeter is 40 units. Write and solves system of equations to determine the length and width of the rect      Log On


   

Question 1130043: The difference between the length and width of a rectangle is 2 units. The perimeter is 40 units. Write and solves system of equations to determine the length and width of the rectangle
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39625) About Me  (Show Source):
You can put this solution on YOUR website!
y length
x width

system%28y-x=2%2Cx%2By=40%2F2%29

You can do the steps.

Answer by MathTherapy(10555) About Me  (Show Source):
You can put this solution on YOUR website!

The difference between the length and width of a rectangle is 2 units. The perimeter is 40 units. Write and solves system of equations to determine the length and width of the rectangle
Let the DIMENSIONS be x and y

Then we get: x - y = 2 -------- eq (i)

Also, x + y = 20 ------- eq (ii)

Solve by adding the 2 equations, thereby eliminating y and finding the value of x

Substitute value of x into EITHER eq (i) or (ii) to find y.

You have found the DIMENSIONS of the rectangle.