SOLUTION: Solve the system by the addition method. Identify any dependent systems. 2x + 3y = 5 3y = 5 - 2x

Algebra ->  Systems-of-equations -> SOLUTION: Solve the system by the addition method. Identify any dependent systems. 2x + 3y = 5 3y = 5 - 2x       Log On


   



Question 1124132: Solve the system by the addition method. Identify any dependent systems.
2x + 3y = 5
3y = 5 - 2x

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

2x+%2B+3y+=+5
3y+=+5+-+2x-> move -2x to the left
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2x+%2B+3y+=+5
2x%2B3y+=+5
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Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition


Lets start with the given system of linear equations

2%2Ax%2B3%2Ay=5
2%2Ax%2B3%2Ay=5

In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).

So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.

So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 2 and 2 to some equal number, we could try to get them to the LCM.

Since the LCM of 2 and 2 is 2, we need to multiply both sides of the top equation by 1 and multiply both sides of the bottom equation by -1 like this:

1%2A%282%2Ax%2B3%2Ay%29=%285%29%2A1 Multiply the top equation (both sides) by 1
-1%2A%282%2Ax%2B3%2Ay%29=%285%29%2A-1 Multiply the bottom equation (both sides) by -1


So after multiplying we get this:
2%2Ax%2B3%2Ay=5
-2%2Ax-3%2Ay=-5

Notice how 2 and -2 add to zero, 3 and -3 add to zero, 5 and -5 and to zero (ie 2%2B-2=0) 3%2B-3=0, and 5%2B-5=0)


So we're left with

0=0


which means any x or y value will satisfy the system of equations. So there are an infinite number of solutions


So this system is dependent