SOLUTION: Given that (4,10) is a solution to the following systems of equations, find the values of "A" and "B" {{{ (A+2)x - By = 0 }}} {{{x^2 + (A-2)x - 2By = 0}}}

Algebra ->  Systems-of-equations -> SOLUTION: Given that (4,10) is a solution to the following systems of equations, find the values of "A" and "B" {{{ (A+2)x - By = 0 }}} {{{x^2 + (A-2)x - 2By = 0}}}      Log On


   

Question 1081792: Given that (4,10) is a solution to the following systems of equations, find the values of "A" and "B"
+%28A%2B2%29x+-+By+=+0+ x%5E2+%2B+%28A-2%29x+-+2By+=+0
Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!

Instead of just doing it for you,  I'll do one exactly like it
so you can follow it step by step.

Given that (6,9) is a solution to the following systems of equations, 
find the values of "A" and "B"

+%28A%2B3%29x+-+By+=+0+           x%5E2+%2B+%28A-3%29x+-+3By+=+0

Substitute x=6 and y=9 in both:

+%28A%2B3%29%286%29+-+B%289%29+=+0+           %286%29%5E2+%2B+%28A-3%29%286%29+-+3B%289%29+=+0

+6%28A%2B3%29+-+9B+=+0+           36+%2B+6%28A-3%29+-+27B+=+0

+6A%2B18+-+9B+=+0+           36+%2B+6A-18+-+27B+=+0

+6A-+9B+=+-18+           6A-+27B+=+-18

Divide both equations through by 3

+2A-+3B+=+-6+           2A-+9B+=+-6

 2A - 3B = -6
 2A - 9B = -6

Subtracting the 2nd equation from the first:

      6B = 0
       B = 0

Substituting in the first

 2A - 3(0) = -6
        2A = -6
         A = -3

Now do yous exactly like this one, step by step.

Edwin