SOLUTION: Mark made a business trip of 181 miles. He averaged 61 mph for the first part of the trip and 60 mph for the second part. If the trip took 3 hours, how long did he travel at each

Algebra ->  Systems-of-equations -> SOLUTION: Mark made a business trip of 181 miles. He averaged 61 mph for the first part of the trip and 60 mph for the second part. If the trip took 3 hours, how long did he travel at each      Log On


   

Question 1028107: Mark made a business trip of 181 miles. He averaged 61 mph for the first part of the trip and 60 mph for the second part. If the trip took 3 hours, how long did he travel at each rate?
First part:
Second part:

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
                 rate           time            distance

part 1           61               x               61x

part 2           60               y               60y

total                            3                181

Answer by MathTherapy(10555) About Me  (Show Source):
You can put this solution on YOUR website!

Mark made a business trip of 181 miles. He averaged 61 mph for the first part of the trip and 60 mph for the second part. If the trip took 3 hours, how long did he travel at each rate?
First part:
Second part:
Let time he traveled at 61 mph, be T

Then time traveled at 60 mph = 3 - T

We then get the following DISTANCE equation: 61T + 60(3 - T) = 181

61T + 180 - 60T = 181

61T = 60T = 181 - 180

T, or time he traveled at 61 mph = highlight_green%28matrix%281%2C2%2C+1%2C+hour%29%29

Time he traveled at 60 mph: 3 - 1, or highlight_green%28matrix%281%2C2%2C+2%2C+hours%29%29