Tutors Answer Your Questions about Surface-area (FREE)
Question 194600: a fabricating shoop has dimensions 80'x100' with a 15' ceiling its ventilating system can evacuate 5200 cu ft. per minute. if there was a poisonous gas leak in the shop how long would it take to exchange all the air in the shop to the nearest minute?
Thanks Tammy
Click here to see answer by ankor@dixie-net.com(22740)   |
Question 195460: Please help to resolve this problem. It has 3 parts.
1. A running track 4 m wide goes around a soccer field that is twice as long as it is wide. At each end of the soccer field the track is a semi-circle with inner radius is r. Find the formula for the area of the track in terms of (pi) and r.
1a. Suppose that you plan to run once around the track described in problem above, if you stay 0.5 m from the inner edge of the track, how far will you run? (Hint: The circumfrence of a circle is 2(pi)r. Your anwser will be in terms of pi and r).
1b. Suppose that a friend stays 0.5 m from the outer edge of the track. How much farther does your friend run than you do?
Thanks a lot for your help.
Click here to see answer by solver91311(24713)  |
Question 196935: construct a barrel(shape of a right cylinder) to hold 150gals need top and bottom diameter 2 1/2ft. what must the height of the barrel be to the nearest 1/2in.?
I've got the circumference of the barrel to be 94in. would I use perimeter or what? HELP!
Thanks tammy
Click here to see answer by ankor@dixie-net.com(22740) |
Question 197029: Find the area of a square whose perimeter is 32 inches? Multiple Choice: A.)8square inches, B.) 16, C.) 32, D.)64 But no measurements are given...If I had measurements I could do something but I guess that's what I am supposed to fiqure out right? I suck at geometry!!
Click here to see answer by jim_thompson5910(35256) |
Question 197372: I don't understand how to find the area in this question using the information given, the Question asks: The perimeter of a Trapezoid is 29 inches. Its nonparallel sides are 4 inches and 5 inches long. If the height of the trapezoid is 3 inches, find its area.
Click here to see answer by solver91311(24713) |
Question 198115: The radius of a can soup is 2 in. and the height is 7 in.
Is there enough information in the diagram to calculate the area of the label? If so, calculate the area of the label (Use pi = 22/7) If not, explain what additional information would be necessary.
Click here to see answer by RAY100(1637) |
Question 198114: The radius of a can soup is 2 in. and the height is 7 in.
If the radius of the can is cut in half and the height is doubled, what effect will this have on the amount of soup in the can? Provide a mathematical explanation of your answer.
Click here to see answer by RAY100(1637) |
Question 198076: scale model of the greate pyramid. he finds out it has a square base which is 230 meters on each side. it is 147 meters tall, and each face has a slant height of 186 meters. each face was once covered with limestone
what was the lateral surface area of the limestone.
Click here to see answer by arallie(162) |
Question 198670: 1. A semicircular window of radius 12 inches is to be laminated with a sunblock coating that costs $0.75 per square inch to apply. What is the total cost of coating the window, to the nearest cent? (Use п = 3.14. Hint: Area of Circle: A = пrē)
Click here to see answer by jojo14344(1513) |
Question 198670: 1. A semicircular window of radius 12 inches is to be laminated with a sunblock coating that costs $0.75 per square inch to apply. What is the total cost of coating the window, to the nearest cent? (Use п = 3.14. Hint: Area of Circle: A = пrē)
Click here to see answer by nerdybill(7384)  |
Question 198847: Directions state: Find the perimeters and areas of the squares and rectangles in questions 7-10.
The figure shown in the text has a picture of a square which is dissected in the middle to form two right triangles. The triangle has two 45 degree and one 90 degree angles. All that is given is six square root of two (6 square root 2) for the hypotenuse of the adjacent right triangles. My apoogies but I do not have a square root symbol key on my computer keyboard. As you can tell I need to solve for the perimeter and area, but I do not even know how to without data given for either side one or side two.
Click here to see answer by jim_thompson5910(35256) |
Question 198847: Directions state: Find the perimeters and areas of the squares and rectangles in questions 7-10.
The figure shown in the text has a picture of a square which is dissected in the middle to form two right triangles. The triangle has two 45 degree and one 90 degree angles. All that is given is six square root of two (6 square root 2) for the hypotenuse of the adjacent right triangles. My apoogies but I do not have a square root symbol key on my computer keyboard. As you can tell I need to solve for the perimeter and area, but I do not even know how to without data given for either side one or side two.
Click here to see answer by solver91311(24713) |
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Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980, 1981..2025, 2026..2070, 2071..2115, 2116..2160, 2161..2205, 2206..2250, 2251..2295, 2296..2340, 2341..2385, 2386..2430, 2431..2475, 2476..2520, 2521..2565, 2566..2610, 2611..2655, 2656..2700, 2701..2745, 2746..2790, 2791..2835, 2836..2880, 2881..2925, 2926..2970, 2971..3015, 3016..3060, 3061..3105, 3106..3150, 3151..3195, 3196..3240, 3241..3285, 3286..3330, 3331..3375, 3376..3420, 3421..3465, 3466..3510, 3511..3555, 3556..3600, 3601..3645, 3646..3690, 3691..3735, 3736..3780, 3781..3825, 3826..3870, 3871..3915, 3916..3960, 3961..4005, 4006..4050, 4051..4095, 4096..4140, 4141..4185, 4186..4230, 4231..4275, 4276..4320, 4321..4365, 4366..4410, 4411..4455, 4456..4500, 4501..4545, 4546..4590, 4591..4635, 4636..4680, 4681..4725, 4726..4770, 4771..4815, 4816..4860, 4861..4905, 4906..4950, 4951..4995, 4996..5040, 5041..5085, 5086..5130, 5131..5175, 5176..5220, 5221..5265, 5266..5310, 5311..5355, 5356..5400, 5401..5445, 5446..5490, 5491..5535, 5536..5580, 5581..5625, 5626..5670, 5671..5715, 5716..5760, 5761..5805, 5806..5850, 5851..5895, 5896..5940, 5941..5985, 5986..6030, 6031..6075, 6076..6120, 6121..6165, 6166..6210, 6211..6255, 6256..6300, 6301..6345, 6346..6390, 6391..6435, 6436..6480, 6481..6525, 6526..6570, 6571..6615, 6616..6660, 6661..6705, 6706..6750, 6751..6795, 6796..6840
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