Question 1210338: Determine the perimeter and area:
https://i.ibb.co/ZzVXsg2g/ED907482-977-D-4-DD4-9636-317-CA1-C38-D45.jpg Found 2 solutions by ikleyn, mccravyedwin:Answer by ikleyn(52781) (Show Source):
You can put this solution on YOUR website! .
Determine the perimeter and area:
https://i.ibb.co/ZzVXsg2g/ED907482-977-D-4-DD4-9636-317-CA1-C38-D45.jpg
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The perimeter is (5 + 5) + (6+6) + = = 34.5663706 m.
The area is the sum of the areas of two right-angled triangles PLUS the area of the rectangle
PLUS the area of the semi-circle of the radius 8/2 = 4 m
Right angled triangles are (3-4-5)-triangles. The area of each such triangle is (1/2)*3*4 = 3*2 = 6 m^2.
So, the area under the question is
2*6 + 6*8 + = = 85.1327412 m^2.
Solved, with explanations.
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This problem is EXTREMELY simple.
It is of the level " take what you see in the picture,
and plug the numbers into the simple formula ".
The triangle at the top has:
Its two slanted sided contribute 2(5m) = 10m to the perimeter.
The rectangle in the middle has:
It's left and right sides contribute 2(6m) = 12m to the perimeter.
The semi-circle at the bottom has diameter 8m and therefor 4m radius:
m2.
It contributes m to the circumference.
m2 m.
Edwin
