SOLUTION: The area of the rectangle is represented by 5x^2 + 19x + 12. What is the length? Width=5x + 4

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Question 983388: The area of the rectangle is represented by 5x^2 + 19x + 12. What is the length?
Width=5x + 4

Found 3 solutions by jim_thompson5910, mananth, josgarithmetic:
Answer by jim_thompson5910(35256)   (Show Source):
You can put this solution on YOUR website!
Notice how the last term of 5x^2 + 19x + 12 is 12

The constant term of 5x+4 is 4.

Divide: 12/4 = 3

So the constant term in the length must be 3.

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The first term in the area expression is 5x^2. The first term in the width is 5x. Divide: 5x^2 over 5x = x

So the variable term must be just x.

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The length is (x+3)

(x+3)*(5x+4) = 5x^2 + 19x + 12

Answer by mananth(16946)   (Show Source):
You can put this solution on YOUR website!
The area of the rectangle is represented by 5x^2 + 19x + 12.
Width=5x + 4

Area = L * W
= L * (5x+4)
l=
length = (x+3)

Answer by josgarithmetic(39617)   (Show Source):
You can put this solution on YOUR website!
Do you know how to perform polynomial division?
You have , and ;
if your length is L, then .

Solving the formula for L, you have .
This means A divided by w.

Now, with that discussed, and hopefully understood, if you know polynomial division, then do it. If not, I will help with the polynomial division.