SOLUTION: If the perimeter is 86,and the length is 25, then what is the width? I've tried a rule that said the width is four times less than the length, but that did not work for this proble
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-> SOLUTION: If the perimeter is 86,and the length is 25, then what is the width? I've tried a rule that said the width is four times less than the length, but that did not work for this proble
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Question 964762: If the perimeter is 86,and the length is 25, then what is the width? I've tried a rule that said the width is four times less than the length, but that did not work for this problem because the perimeter added up to 92 instead of 86 inches. Answer by macston(5194) (Show Source):
You can put this solution on YOUR website! .
W=width; L=length=25; P=perimeter=86
P=2(L+W) This is one formula to find perimeter.
P/2=L+W
(P/2)-L=W Plug in values and solve.
(86/2)-25=W
43-25=W
18=W
CHECK:
P=2(L+W)
86=2(25+18)
86=2(43)
86=86