SOLUTION: If r = 7 cm and h = 5 cm, what is the approximate surface area of the cylinder? (Use 3.14 for pi.)

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Question 961500: If r = 7 cm and h = 5 cm, what is the approximate surface area of the cylinder? (Use 3.14 for pi.)
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

Well if you can make the cylinder with the rectangle and the two circles, you can use them to derive the surface area of the cylinder.
The area of the two circles is straightforward. The area of one circle is pi+%2Ar%5E2, so for two circles, you get 2+%2A+pi+%2A+r%5E2
-the longest side or folded side of the rectangle must be equal to 2+%2A+pi+%2A+r, which is the circumference of the circle
To get the area of the rectangle, multiply h by 2%2A+pi+%2A+r and that is equal to 2+%2A+pi+%2A+r+%2Ah.
Therefore, the total surface area of the cylinder, call it SA is:
SA+=+2+%2A+pi+%2A+r%5E2+%2B+++2+%2A+pi+%2A+r+%2Ah........plug in given values r+=+7cm and h+=+5cm

SA+=+2+%2A+3.14+%2A+%287cm%29%5E2+%2B+++2+%2A+3.14%2A%287cm%29+%2A%285cm%29
SA+=+6.28+%2A+49cm%5E2+%2B+++6.28%2A7cm+%2A5cm
SA+=+307.72cm%5E2+%2B++219.8cm%5E2
SA+=+527.52cm%5E2