SOLUTION: If the area of the center square is four square units, what is the area of the regular octagon? Here is an image: http://postimg.org/image/icik0myl1/ Thank you!!

Algebra ->  Surface-area -> SOLUTION: If the area of the center square is four square units, what is the area of the regular octagon? Here is an image: http://postimg.org/image/icik0myl1/ Thank you!!      Log On


   

Question 936232: If the area of the center square is four square units, what is the area of the regular octagon? Here is an image: http://postimg.org/image/icik0myl1/


Thank you!!
Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
The area of a regular octagon = 2(1 + square root(2))*a^2, where a is the length of a side
Since the area of the square in the middle is 4, the length of a side is 2, and a^2 = 4 + 4 = 8 and a = 2*square root(2) and a^2 = 8
The area of the regular octagon = 2(1 + square root(2))*8 = 38.627416998 square units