SOLUTION: My diagram shoes two squares.The sum of their area is 58m2.The sum of the lengths of their side is10m..Find values for x and y(y >x)..no idea how to go about this..Thanks

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Question 914554: My diagram shoes two squares.The sum of their area is 58m2.The sum of the lengths of their side is10m..Find values for x and y(y >x)..no idea how to go about this..Thanks
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
x, the side of one of the squares
y, the side of the other square

First condition: x%5E2%2By%5E2=58

Second condition: 4x%2B4y=10

Solving the two equations for x and y is arithmetic using variables. Simplify the perimeter sum equation and solve it for one of the variables; and substitute this into the area sum equation; solve for the value of the single variable, and then use the result in the perimeter sum equation for the value of the other variable.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
My diagram shoes two squares.The sum of their area is 58m2.The sum of the lengths of their side is10m..Find values for x and y(y >x)..no idea how to go about this..Thanks

One side of 1st square: x
Area of 1st square: x%5E2
One side of 2nd square: y
Area of 2nd square: y%5E2
Sum of their areas is 58m%5E2, so: x%5E2+%2B+y%5E2+=+58 ------ eq (i)
Sum of the lengths of a side of each square is 10, so: x + y = 10____y = 10 - x ------ eq (ii)
x%5E2+%2B+%2810+-+x%29%5E2+=+58 ------- Substituting 10 - x for y in eq (i)
x%5E2+%2B+100+-+20x+%2B+x%5E2+=+58
x%5E2+%2B+x%5E2+-+20x+%2B+100+-+58+=+0
2x%5E2+-+20x+%2B+42+=+0
2%28x%5E2+-+10x+%2B+21%29+=+2%280%29
x%5E2+-+10x+%2B+21+=+0
(x - 7)(x - 3) = 0
highlight_green%28x+=+7%29 OR highlight_green%28x+=+3%29
If x = 7, then y = 3
If x = 3, then y = 7
However, since y > x, then the latter is the correct choice.