SOLUTION: The base of a rectangle is twice the side of a square, and the height of the rectangle is two more than the side of the square. The area of the rectangle is 32 square inch units mo

Algebra ->  Surface-area -> SOLUTION: The base of a rectangle is twice the side of a square, and the height of the rectangle is two more than the side of the square. The area of the rectangle is 32 square inch units mo      Log On


   

Question 89445: The base of a rectangle is twice the side of a square, and the height of the rectangle is two more than the side of the square. The area of the rectangle is 32 square inch units more than the area of the square. Find the dimensions of the rectangle.
Answer by checkley75(3666) About Me  (Show Source):
You can put this solution on YOUR website!
THE SQUARE AREA =X^2
THE AREA OF THE RECTANGLE = 2X(X+2)
2X(X+2)-32=X^2
2X^2+4X-32=X^2
2X^2-X^2+4X-32=0
X^2+4X-32=0
(X-4)(X+8)=0
X-4=0
X=4 ANSWER FOR THE SIDES OF THE SQUARE.
SIDES OF THE RECTANGLE ARE 2*4=8 & 2(4+2)=2*8=16. THE SIDES OF THE RECTANGLE ARE 8 & 16.
PROOF
2*4(4+2)-32=4^4
8*6-32=16
48-32=16
16=16