SOLUTION: Jim’s room is the shape of a rectangle. He wants to put carpet on the floor. The length of the room is 11m and the width is 9m. Both measurements are given to the nearest meter.

Algebra ->  Surface-area -> SOLUTION: Jim’s room is the shape of a rectangle. He wants to put carpet on the floor. The length of the room is 11m and the width is 9m. Both measurements are given to the nearest meter.       Log On


   



Question 863625: Jim’s room is the shape of a rectangle. He wants to put carpet on the floor.
The length of the room is 11m and the width is 9m.
Both measurements are given to the nearest meter.
Find the lower bound of the area of the room

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
A+=+Lw+=+%2810.5%29%288.5%29
the lower bound of the area of the room
10.5 is the smallest number that would 'round Up' to 11
8.5 is the smallest number that would 'round Up' to 9
therefore, the smallest the Area could be is %2810.5%29%288.5%29