SOLUTION: can someone please help me, i really need help with these ones. they are confusing me
Find the area:
A square with diagnol 8
diagonal squared = 2.(side)squared
Algebra ->
Surface-area
-> SOLUTION: can someone please help me, i really need help with these ones. they are confusing me
Find the area:
A square with diagnol 8
diagonal squared = 2.(side)squared
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Question 86330: can someone please help me, i really need help with these ones. they are confusing me
Find the area:
A square with diagnol 8
diagonal squared = 2.(side)squared
8.8 = 2.(side)squared
32 = (side)squared
side = square root of 32=4.sqrt.2
therefore area of a square= side.side = 4.sqrt2.4.sqrt2=32
area of 45-45-90 triangle with hypotenuse of 2sqrt6
since the angles of the other two sides are equal their corresponding sides are
equal. hence (hypo)sq=(side)sq+(side)sq
(2sqrt6)square = 2.(side)square
4.6/2 = (side)square
12=(side)square side= 2.sqrt3
area of the triangle = 1/2.base.height
= 1/22.sqrt3.2.sqrt3 = 2.3 = 6
area of rhombus = 1/2.product of diagonals
= 1/2.18.15 = 135 .
a hexagon has six equilateral triangles hence area of hexgon = sum of the area
of all the triangles.
area of an equilateral triangle= sqrt3.side square/4=sqrt3.10.10/4=25sqrt3
area of the hexagon = 6.25.sqrt3 = 150.sqrt3.
A 45-45-90 triangle with hyptonenuse of 2 square root of 6
A rhombus with diagonals 18 and 15
A regular hexagon with sides of 10 cm Answer by praseenakos@yahoo.com(507) (Show Source):
