SOLUTION: Find the area bounded by f(x) and p(x) on [-1,2] using an antiderividant theory where as: f(x) = x^2 p(x) = x + 2 ... and graph

Algebra ->  Surface-area -> SOLUTION: Find the area bounded by f(x) and p(x) on [-1,2] using an antiderividant theory where as: f(x) = x^2 p(x) = x + 2 ... and graph      Log On


   



Question 85498: Find the area bounded by f(x) and p(x) on [-1,2] using an antiderividant theory where as:
f(x) = x^2
p(x) = x + 2
... and graph

Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
graph%28300%2C300%2C-5%2C5%2C-5%2C5%2Cx%5E2%2Cx%2B2%29
Dominant: x + 2
Recessive: x^2
int%28+p%28x%29+-+f%28x%29%2C+dx%2C+-1%2C+2+%29
int%28+x+%2B+2+-+x%5E2%2C+dx%2C+-1%2C+2+%29
x%5E2%2F2+%2B+2x+-+x%5E3%2F3 | 2 / -1
(x^2/2 + 2x - x^3/3) - (x^2/2 + 2x - x^3/3)
(2^2/2 + 2*2 - 2^3/3) - ((-1)^2/2 + 2*-1 - (-1)^3/3)
(2 + 4 - 8/3) - (1/2 - 2 + 1/3)
2 + 4 - 8/3 - 1/2 + 2 - 1/3
8 - 9/3 - 1/2
7 1/2 - 3
4 1/2 units^2