SOLUTION: The area of rectangle lies between 40cm^2 and 45cm^2. If one of the sides is 5 cm, then its diagonal lies between? (a) 8cm and 10 cm (b)9cm and 11cm (c)10cm and 12cm (d)11cm an

Algebra ->  Surface-area -> SOLUTION: The area of rectangle lies between 40cm^2 and 45cm^2. If one of the sides is 5 cm, then its diagonal lies between? (a) 8cm and 10 cm (b)9cm and 11cm (c)10cm and 12cm (d)11cm an      Log On


   

Question 839637: The area of rectangle lies between 40cm^2 and 45cm^2. If one of the sides is 5 cm, then its diagonal lies between?
(a) 8cm and 10 cm
(b)9cm and 11cm
(c)10cm and 12cm
(d)11cm and 13cm
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,



Note:  Area is in cm^2

The area of rectangle lies between 40cm^2 and 45cm^2. (If one of the sides is 5 cm)

Using the Pythagorean Theorem

A = 40cm^2 (8cmx5cm) ⇒  diagonal = sqrt%288%5E2+%2B+5%5E2%29+=+sqrt%2889%29+=+9.4

A = 45cm^2 (9cmx5cm)  ⇒  diagonal = sqrt%289%5E2+%2B+5%5E2%29+=+sqrt%28106%29=+10.3

Wish You the Best in your Studies.