SOLUTION: The radius of a cylindrical gift box is (2x+3) in. The height of the gift box is twice the radius. What is the surface area of the cylinder? Write your answer as a polynomial in st

Algebra ->  Surface-area -> SOLUTION: The radius of a cylindrical gift box is (2x+3) in. The height of the gift box is twice the radius. What is the surface area of the cylinder? Write your answer as a polynomial in st      Log On


   



Question 815486: The radius of a cylindrical gift box is (2x+3) in. The height of the gift box is twice the radius. What is the surface area of the cylinder? Write your answer as a polynomial in standard form.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
The radius of a cylindrical gift box is (2x+3) in. The height of the gift box is twice the radius. What is the surface area of the cylinder? Write your answer as a polynomial in standard form.
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The SA of each end is pi*r^2
The lateral SA is 2*pi*r*h
Multiply and add
I'll be glad to check your work.