You can put this solution on YOUR website! Consider that on either side of the diagonal we have a triangle
with side lengths 34 , 20 , and 42.
So if we can find the total area of the two triangles we will have
the area of the parallelogram.
We can use Heron's formula to find the area of one of the triangles.
First we find s ( 1/2 the perimeter )
s = (1/2)*(34 + 20 + 42)
s = (1/2)*(96)
s = 48
The formula for the area A is A = sq-rt(s*(s-a)(s-b)(s-c))
so A = sq-rt( 48 * (48-34) * (48-20) * (48-42) )
A = sq-rt( 48 * 14 * 28 * 6 )
A = sq-rt( 112896 )
A = 336
The area of the parallelogram is twice 336 or 672.