SOLUTION: The equation of a certain circle is x+y+6x-4y+8=0
i) find the equation of a tangent from the point (-1,5)
ii) the length of the tangent
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-> SOLUTION: The equation of a certain circle is x+y+6x-4y+8=0
i) find the equation of a tangent from the point (-1,5)
ii) the length of the tangent
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Question 807860: The equation of a certain circle is x+y+6x-4y+8=0
i) find the equation of a tangent from the point (-1,5)
ii) the length of the tangent Found 2 solutions by Alan3354, richwmiller:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! The equation of a certain circle is x+y+6x-4y+8=0
i) find the equation of a tangent from the point (-1,5)
ii) the length of the tangent
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That's not a circle, it's a straight line.
You can put this solution on YOUR website! x+y+6x-4y+8=0
is a straight line not a circle.
perhaps you mean
x^2+y^2+6x-4y+8=0
but (-1,5) is not on that circle
