SOLUTION: plot the equation 3x+4y=7 on the graph paper taking four points. also plot the equation y=x on the same graph paper. at what point do the two lines meet?

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Question 789115: plot the equation 3x+4y=7 on the graph paper taking four points. also plot the equation y=x on the same graph paper. at what point do the two lines meet?
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
To graph one line you only need to plot two points and connect them with a straight line. Since the problem asks for 4 points, we do the extra unnecessary work.

For 3x%2B4y=7,
3x%2B4y=7-->4y=7-3x-->y=%287-3x%29%2F4, so chosing random values for x we would get lots of fractions.
However, substituting x=1gives us
{{y=(7-3)/4=4/4=1)}}} and we have the point (1,1).
Increasing or decreasing x by 4 gives us other integer values for y:
Substituting x=5gives us
y=%287-3%285%29%29%2F4=%287-15%29%2F4=-8%2F4=-2 and we have the point (5,-2).
Substituting x=-3gives us
y=%287-3%28-3%29%29%2F4=%287%2B9%29%2F4=16%2F4=4 and we have the point (-3,4).
Substituting x=-7gives us
y=%287-3%28-7%29%29%2F4=%287%2B21%29%2F4=28%2F4=7 and we have the point (-7,7).

For y=x, nice points are easier to find:
We could substitute a few scattered values for x, to get
x=4-->y=4 for point (4,4),
x=8-->y=8 for point (8,8),
x=-4-->y=-4 for point (-4,-4), and
y=-8-->y=-8 for point (-8,-8)

The lines seem to intersect at point (1,1), so system%28x=1%2Cy=1%29 seems to be the solution.
We need to verify by substituting in the original equations:
For 3x%2B4y=7, 3%2A1%2B4%2A1=3%2B4=7 checks
For y=x, 1=1 checks.
So highlight%28system%28x=1%2Cy=1%29%29 is the solution.