SOLUTION: The perimeter of a triangle is 75 feet. What is the largest possible area?

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Question 785527: The perimeter of a triangle is 75 feet. What is the largest possible area?
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
The largest possible area requires an equilateral triangle.
An equilateral triangle with a perimeter of 75 feet eill have side length of
75%2F3feet=25feet
The area of a triangle with sides of length a and b forming an angle C is
%281%2F2%29%2Aa%2Ab%2Asin%28C%29
The angles in an equilateral triangle measure 60%5Eo
The area of our largest triangle is
square+feet
625sqrt%283%29%2F4=156.25sqrt%283%29 would be the exact number of square feet, but I would round/approximate it as 271 square feet.

How do I know we need an equilateral triangle?
Heron's formula says that the area of a triangle with side length a, b, and c is
sqrt%28s%28s-a%29%28s-b%29%28s-c%29%29, where s=%28a%2Bb%2Bc%29%2F2 is the semi=perimeter (half of the perimeter).
If the perimeter is fixed (75 feet), s = 37.5 feet, is also fixed.
For maximum area we need to maximize %28s-a%29%28s-b%29%28s-c%29
I am not sure how to prove it with 3 dimensions, but since enlarging one of those factors requires making one or both of the other two smaller, I believe that the maximum product requires s-a=s-b=s-c, which translates into a=b=c.