SOLUTION: Select the equation for the circle with center at point (2, –5) and a radius of 12. A.(x - 2)2 + (y + 5)2 = 12 B.(x + 2)2 + (y - 5)2 = 12 C.(x - 2)2 + (y + 5)2 = 144 D.(x + 2

Algebra ->  Surface-area -> SOLUTION: Select the equation for the circle with center at point (2, –5) and a radius of 12. A.(x - 2)2 + (y + 5)2 = 12 B.(x + 2)2 + (y - 5)2 = 12 C.(x - 2)2 + (y + 5)2 = 144 D.(x + 2      Log On


   

Question 760795: Select the equation for the circle with center at point (2, –5) and a radius of 12.
A.(x - 2)2 + (y + 5)2 = 12 B.(x + 2)2 + (y - 5)2 = 12
C.(x - 2)2 + (y + 5)2 = 144 D.(x + 2)2 + (y - 5)2 = 144
Found 2 solutions by kjmg, MathTherapy:
Answer by kjmg(1) About Me  (Show Source):
You can put this solution on YOUR website!
Select the equation for the circle with center at point (2, –5) and a radius of 12.
A.(x - 2)2 + (y + 5)2 = 12 B.(x + 2)2 + (y - 5)2 = 12
C.(x - 2)2 + (y + 5)2 = 144 D.(x + 2)2 + (y - 5)2 = 144




the equation of Circle is (x-h)^2 + (y-K)^2 = r^2.
(2, -5) substituting it to the equation, (x-(-2))^2 + (y-(5))^2 = (12)^2.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

Select the equation for the circle with center at point (2, –5) and a radius of 12.
A.(x - 2)2 + (y + 5)2 = 12 B.(x + 2)2 + (y - 5)2 = 12
C.(x - 2)2 + (y + 5)2 = 144 D.(x + 2)2 + (y - 5)2 = 144

%28x+-+2%29%5E2+%2B+%28y+%2B+5%29%5E2+=+144 CHOICE highlight_green%28C%29.

You can do the check!!

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