SOLUTION: Use the quadratic formula to solve a) p^2+√(2p) = 4 b) 2√(5m^2)+3m-4√5=0 Can you please help me out? Thanks so much in advance:)

Algebra ->  Surface-area -> SOLUTION: Use the quadratic formula to solve a) p^2+√(2p) = 4 b) 2√(5m^2)+3m-4√5=0 Can you please help me out? Thanks so much in advance:)      Log On


   

Question 737188: Use the quadratic formula to solve
a) p^2+√(2p) = 4
b) 2√(5m^2)+3m-4√5=0
Can you please help me out? Thanks so much in advance:)
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
They are both more complicated than to immediately use the quadratic formula.

Checking just question #a,
p^2-4=-sqrt(2p)
4-p^2=sqrt(2p)
16-8p^2+p^4=2p
-16+8p^2-p^4=-2p
-p^4+8p^2-16+2p=0
p^4-8p^2-2p+16=0

Next I would make a substitution of r=p^2 and solve first for r using the quadratic formula.

The problem seems like one I have never seen in College Algebra and neither in Intermediate Algebra. You also would need p=+-+sqrt%28r%29 and p=sqrt%28r%29.