SOLUTION: A can has a height of 5.5 inches and a radius of 2.2 inches. A label needs to be placed on the can so that it wraps around the can exactly once with no overlap. What would be the

Algebra ->  Surface-area -> SOLUTION: A can has a height of 5.5 inches and a radius of 2.2 inches. A label needs to be placed on the can so that it wraps around the can exactly once with no overlap. What would be the      Log On


   

Question 727729: A can has a height of 5.5 inches and a radius of 2.2 inches. A label needs to be placed on the can so that it wraps around the can exactly once with no overlap. What would be the surface area of the label? Use 3.14 for pi. Please help!! I'm unsure of what formula to use.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The area of the label is ( circumference of can ) x ( height of can )
+C+=+2%2Api%2Ar+
+C+=+2%2A2.2%2Api+
+C+=+4.4%2A3.14159+
+C+=+13.823+
+5.5%2A13.823+=+76.026+ in2