SOLUTION: The question states: You want to mat and frame an 8x10 photograph. The perimeter of the outside of the mat is 60 inches, The mat is THREE TIMES as wide at the top and bottom as it

Algebra ->  Surface-area -> SOLUTION: The question states: You want to mat and frame an 8x10 photograph. The perimeter of the outside of the mat is 60 inches, The mat is THREE TIMES as wide at the top and bottom as it      Log On


   



Question 649172: The question states:
You want to mat and frame an 8x10 photograph. The perimeter of the outside of the mat is 60 inches, The mat is THREE TIMES as wide at the top and bottom as it is at the sides. Find the dimensions of the mat.

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

the dimensions of the mat: length L and width W
The perimeter P of the outside of the mat is 60in
P=2L%2B2W....=>...2%28L%2BW%29=60in..=>...%28L%2BW%29=30in
L%2BW=30in....1
the mat is THREE TIMES as wide at the top and bottom as it is at the sides
L=3W................2...plug it in equation 1
L%2BW=30in....1
3W%2BW=30in
4W=30in
W=30in%2F4
highlight%28W=7.5in%29
now find
L=3W................2
L=3%2A7.5in
L=highlight%2822.5in%29