SOLUTION: please help me verify which answer is correct#1 or #2 ? A rectangular box with a square base is open at the top and has a volume of 12 cubic feet. Each side of the base has a l

Algebra ->  Surface-area -> SOLUTION: please help me verify which answer is correct#1 or #2 ? A rectangular box with a square base is open at the top and has a volume of 12 cubic feet. Each side of the base has a l      Log On


   



Question 643391: please help me verify which answer is correct#1 or #2 ?
A rectangular box with a square base is open at the top and has a volume of 12 cubic feet. Each side of the base has a length of x feet. Which of the following expresses the surface area, S,in square feet, of the outside of the box in terms of x ? (CLEP precalculus test)
#1:S=x^2+(48/x) or #2: S= x^2+(24/X)I got #2 but the answer key said #1 is correct answer. It didn't explain Why? please show me how to solve it. Thank you

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

please help me verify which answer is correct#1 or #2 ?
A rectangular box with a square base is open at the top and has a volume of 12 cubic feet. Each side of the base has a length of x feet. Which of the following expresses the surface area, S,in square feet, of the outside of the box in terms of x ? (CLEP precalculus test)
#1:S=x^2+(48/x) or #2: S= x^2+(24/X)I got #2 but the answer key said #1 is correct answer. It didn't explain Why? please show me how to solve it. Thank you

Since base = x, then area of base = x%5E2
Since volume of box = 12 cub. ft, and since Volume = LWH, then we can say that:
x(x)(H) = 12, with H being the height of the box

x%5E2H+=+12 ------ x%5E2+=+12%2FH

x%5E2H+=+12 ------ H+=+12%2Fx%5E2

Since S, or surface area of the OPEN box = L*W (base, or bottom) + 2*L*H (front & rear) + 2*W*H (left and right sides), then we have:
S+=+x%28x%29+%2B+2%28xH%29+%2B+2%28xH%29
S+=+x%5E2+%2B+2xH+%2B+2xH
S+=+x%5E2+%2B+4xH
S+=+x%5E2+%2B+4xH
S+=+x%5E2+%2B+4x%2812%2Fx%5E2%29 ----- Substituting 12%2Fx%5E2 for H
S+=+x%5E2+%2B+4cross%28x%29%2812%2F%28x%29cross%28x%5E2%29%29 ---- Canceling x in numerator and denominator

highlight_green%28S++=+x%5E2+%2B+48%2Fx%29

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