SOLUTION: The area of a square increased by 3 is the same as 35 decreased by 7 times the area. Find the are of the square.
LET: x^2 = Area of a Square
WHERE: x^2 is made greater by 3 = 3
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-> SOLUTION: The area of a square increased by 3 is the same as 35 decreased by 7 times the area. Find the are of the square.
LET: x^2 = Area of a Square
WHERE: x^2 is made greater by 3 = 3
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Question 638634: The area of a square increased by 3 is the same as 35 decreased by 7 times the area. Find the are of the square.
LET: x^2 = Area of a Square
WHERE: x^2 is made greater by 3 = 35 made smaller by 7x^2
CALCULATION
x^2+3=35-7x^2
x^2+3-3=35-3-7x^2
x^2=32-7x^2
x^2+7x^2=32-7x^2+7x^2
8x^2/8=32/8=>[x^2=4]
*When I evaluate the answer, it doesn't check. Answer by MathTherapy(10552) (Show Source):
You can put this solution on YOUR website! The area of a square increased by 3 is the same as 35 decreased by 7 times the area. Find the are of the square.
LET: x^2 = Area of a Square
WHERE: x^2 is made greater by 3 = 35 made smaller by 7x^2
CALCULATION
x^2+3=35-7x^2
x^2+3-3=35-3-7x^2
x^2=32-7x^2
x^2+7x^2=32-7x^2+7x^2
8x^2/8=32/8=>[x^2=4]
*When I evaluate the answer, it doesn't check.
x, or one side of square = 2, or - 2(ignore)
Original area = , or , or square units
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Check
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Area + 3 = 35 - 7(area), OR
4 + 3 = 35 – 7(4)
7 = 35 – 28
7 = 7 (TRUE)
Why do you say that it doesn't check?
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