SOLUTION: Find the area of a regular octagon with a 18.7 m apothem and a side length of 15.5 m
Which answer is it?
a. 145.0 m^2
b. 1059.4 m^2
c. 1159.4 m^2
d. 2318.8 m^2
Algebra ->
Surface-area
-> SOLUTION: Find the area of a regular octagon with a 18.7 m apothem and a side length of 15.5 m
Which answer is it?
a. 145.0 m^2
b. 1059.4 m^2
c. 1159.4 m^2
d. 2318.8 m^2
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Question 634927: Find the area of a regular octagon with a 18.7 m apothem and a side length of 15.5 m
Which answer is it?
a. 145.0 m^2
b. 1059.4 m^2
c. 1159.4 m^2
d. 2318.8 m^2 Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website! Imagine you cut the octagon into triangles by drawing segments from the center to the vertices.
Area of one triangle (in the octagon):
A = (bh)/2
A = (15.5*18.7)/2
A = 144.925
So one triangle has an area of 144.925 m^2. This means that 8 of these equal triangles have a total area of 8*144.925 = 1159.4 m^2
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