SOLUTION: Find the surface area of a cylinder with a base area of 49 π in2 and a height that is twice the radius of its base.
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-> SOLUTION: Find the surface area of a cylinder with a base area of 49 π in2 and a height that is twice the radius of its base.
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Question 632437: Find the surface area of a cylinder with a base area of 49 π in2 and a height that is twice the radius of its base. Found 2 solutions by lwsshak3, ankor@dixie-net.com:Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Find the surface area of a cylinder with a base area of 49 π in2 and a height that is twice the radius of its base.
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formula for surface area of a cylinder=πr√(r^2+h^2), r-radius of circular base, h=height
given area of circular base=49π in^2=πr^2
49π in^2=πr^2
r^2=49
r=√49=7
h=2r=14
..
πr√(r^2+h^2)=π*7√(7^2+14^2)=21.99√(49+196)=21.99√245=344.20
surface area of a cylinder=344.20 in^3
You can put this solution on YOUR website! Find the surface area of a cylinder with a base area of 49 π in2 and
a height that is twice the radius of its base.
:
Find the radius from the given area of the base =
divide both sides by
r^2 = 49
r =
r = 7 inches is the radius
then
14 inches = the height
:
Surface area of a cylinder formula:
A = +
:
A = +
:
A = 307.876 + 615.752
:
A = 923.63 sq/inches
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