SOLUTION: How many square feet is the surface area of the house. The house is 45' by 34'. Each corner is 10'high and the peak of the roof is 14'. I have a lot of questions that require the s
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-> SOLUTION: How many square feet is the surface area of the house. The house is 45' by 34'. Each corner is 10'high and the peak of the roof is 14'. I have a lot of questions that require the s
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Question 616981: How many square feet is the surface area of the house. The house is 45' by 34'. Each corner is 10'high and the peak of the roof is 14'. I have a lot of questions that require the same formula but I can not figure out what the roof has to do with it. If i can get help on the formula i can do the rest. Thank you Answer by solver91311(24713) (Show Source):
The roof is part of the outside surface of the house, the problem is you haven't provided enough information. Which side of the house (the 45' side or the 34' side) is parallel to the ridgeline of the roof? You have two rectangles that form the roof, each having a length that is either 34 or 45 feet and a width that you have to calculate using Pythagoras; that width being the hypotenuse of a right triangle with one leg of 4 feet (14 minus 10) and the other leg being either 17 feet (half of 34) or 22.5 feet (half of 14). Then you need to calculate the areas of the sides of the house. First you have two 10 by 34 rectangles and tow 10 by 45 rectangles. Then, depending on which dimension is parallel to the ridge line, you have two isosceles triangles with bases of 34 or 45 and a height of 4.
John
My calculator said it, I believe it, that settles it
